Sqlalchemy filter by field in list but keep original order?

Question

I have a Shoe model like this:

class Shoe(db.Model):
id = db.Column(db.Integer, primary_key = True)
asin = db.Column(db.String(20), index = True)

Answer 1

I also have the same problem using a MySQL database. This is what I did:

my_list = [13,14,5,6,7]
# convert my_list to str
my_list_str = ','.join(map(str, my_list))

And this is how my query looks like:

checkpoints = (
    db_session.query(Checkpoint)
    .filter(Checkpoint.id.in_(my_list))
    .order_by('FIELD(id, ' + my_list_str + ')')
    .all()
)

FIELD() is a native function in MySQL.

EDIT: So your query should look like this:

my_list_of_ids_str = ','.join(map(str, my_list_of_ids)) 
Shoe.query.filter(Shoe.id.in_(my_list_of_ids)).order_by('FIELD(id, ' + my_list_of_ids_str + ')').all()

Cheers