Get all current (active) subscriptions

Question

Is it possible to get all the \"active\" subscriptions without storing them manually?

I\'d like to unsubscribe all of the \"active\" subscriptions and don\'

Answer 1

I think the basic problem is that an Observable (with exception of Subject and derivatives) does not keep a reference to it's observers.

Without built-in references, you need to handle them externally in some form.

I think the best you could achieve is to create a reusable subscription 'override' to wrap the mechanism, although I doubt it's worth it.

import { Observable } from 'rxjs/Observable';
import { Subscription } from 'rxjs/Subscription';

const subscribeAndGuard = function(component, fnData, fnError = null, fnComplete = null) {

  // Define the subscription
  const sub: Subscription = this.subscribe(fnData, fnError, fnComplete);

  // Wrap component's onDestroy
  if (!component.ngOnDestroy) {
    throw new Error('To use subscribeAndGuard, the component must implement ngOnDestroy');
  }
  const saved_OnDestroy = component.ngOnDestroy;
  component.ngOnDestroy = () => {
    console.log('subscribeAndGuard.onDestroy');
    sub.unsubscribe();
    // Note: need to put original back in place
    // otherwise 'this' is undefined in component.ngOnDestroy
    component.ngOnDestroy = saved_OnDestroy;
    component.ngOnDestroy();

  };

  return sub;
};

// Create an Observable extension
Observable.prototype.subscribeAndGuard = subscribeAndGuard;

// Ref: https://www.typescriptlang.org/docs/handbook/declaration-merging.html
declare module 'rxjs/Observable' {
  interface Observable {
    subscribeAndGuard: typeof subscribeAndGuard;
  }
}

Ref this question Angular/RxJs When should I unsubscribe from Subscription