I have 5 dictionaries and I want a union of their keys.
alldict = [dict1, dict2, dict3, dict4, dict5]
I tried
allkey = reduce(
Your solution works for the first two elements in the list, but then dict1
and dict2
got reduced into a set and that set is put into your lambda as the x
. So now x
does not have the method keys()
anymore.
The solution is to make x be a set from the very beginning by initializing the reduction with an empty set (which happens to be the neutral element of the union).
Try it with an initializer:
allkey = reduce(lambda x, y: x.union(y.keys()), alldict, set())
An alternative without any lambdas would be:
allkey = reduce(set.union, map(set, map(dict.keys, alldict)))