Regular expression with an = and a ;

Question

I\'m trying to use a regular expression to find all substrings that start with an equals sign (=) and ends with a semicolon (;) with any number of char

Answer 1

This looks for "any number of = signs, including 0"

=*;

If you want "= followed by any number of other characters" you want

=.*;

However, that will match greedily - if you want lazy matching (so that it stops one group when it finds the next semicolon) you might want:

=.*?;