pyplot.hist()
documentation specifies that when setting a range for a histogram \"lower and upper outliers are ignored\".
Is it possible to make th
I was also struggling with this, and didn't want to use .clip()
because it could be misleading, so I wrote a little function (borrowing heavily from this) to indicate that the upper and lower bins contained outliers:
def outlier_aware_hist(data, lower=None, upper=None):
if not lower or lower < data.min():
lower = data.min()
lower_outliers = False
else:
lower_outliers = True
if not upper or upper > data.max():
upper = data.max()
upper_outliers = False
else:
upper_outliers = True
n, bins, patches = plt.hist(data, range=(lower, upper), bins='auto')
if lower_outliers:
n_lower_outliers = (data < lower).sum()
patches[0].set_height(patches[0].get_height() + n_lower_outliers)
patches[0].set_facecolor('c')
patches[0].set_label('Lower outliers: ({:.2f}, {:.2f})'.format(data.min(), lower))
if upper_outliers:
n_upper_outliers = (data > upper).sum()
patches[-1].set_height(patches[-1].get_height() + n_upper_outliers)
patches[-1].set_facecolor('m')
patches[-1].set_label('Upper outliers: ({:.2f}, {:.2f})'.format(upper, data.max()))
if lower_outliers or upper_outliers:
plt.legend()
You can also combine it with an automatic outlier detector (borrowed from here) like so:
def mad(data):
median = np.median(data)
diff = np.abs(data - median)
mad = np.median(diff)
return mad
def calculate_bounds(data, z_thresh=3.5):
MAD = mad(data)
median = np.median(data)
const = z_thresh * MAD / 0.6745
return (median - const, median + const)
outlier_aware_hist(data, *calculate_bounds(data))