I want to be able to call a particular method automatically upon construction of a derived object, however I can\'t think how to do it. The following code illustrates. Another a
While @Jeremy Todd's (accepted) answer works and is a widely accepted solution to the problem, it has a drawback: not very IoC and serialization friendly, since your class cannot be properly constructed using new
. Let me introduce a general solution using some C# features. Note that this solution does not require you to use a factory pattern or invoke anything after constructing the object, and it works on any class with just implementing an interface with a single method.
First we declare an interface that our classes will have to implement:
public interface IInitialize {
void OnInitialize();
}
Next we add a static extension class for this interface, and add the Initialize method:
public static class InitializeExtensions
{
public static void Initialize(this T obj) where T: IInitialize
{
if (obj.GetType() == typeof(T))
obj.OnInitialize();
}
}
Now, if we need a class and all of its descendants to call an initializer right after the object is fully constructed, all we need to do is implement IInitialize
and append a line in the constructor:
public class Parent : IInitialize
{
public virtual void OnInitialize()
{
Console.WriteLine("Parent");
}
public Parent()
{
this.Initialize();
}
}
public class Child : Parent
{
public Child()
{
this.Initialize();
}
public override void OnInitialize()
{
Console.WriteLine("Child");
}
}
public class GrandChild : Child
{
public GrandChild()
{
this.Initialize();
}
public override void OnInitialize()
{
Console.WriteLine("GrandChild");
}
}
The trick is that when a derived class calls the extension method Initialize
, that will suppress any calls not made from the actual class.