Get containing path of lua file

Question

I am wondering if there is a way of getting the path to the currently executing lua script file?

This is specifically not the current working directory, which could be

Answer 1

I have written a function getScriptDir which uses the debug information like a few other people have suggested, but this one is going to work everytime (at least in Windows). But the thing is there are quite a few lines of code as it uses another function string.cut which i have created, which separates a string every given pattern, and puts it into a table.

function string.cut(s,pattern)
  if pattern == nil then pattern = " " end
  local cutstring = {}
  local i1 = 0
  repeat
    i2 = nil
    local i2 = string.find(s,pattern,i1+1)
    if i2 == nil then i2 = string.len(s)+1 end
    table.insert(cutstring,string.sub(s,i1+1,i2-1))
    i1 = i2
  until i2 == string.len(s)+1
  return cutstring
end

function getScriptDir(source)
  if source == nil then
    source = debug.getinfo(1).source
  end
  local pwd1 = (io.popen("echo %cd%"):read("*l")):gsub("\\","/")
  local pwd2 = source:sub(2):gsub("\\","/")
  local pwd = ""
  if pwd2:sub(2,3) == ":/" then
    pwd = pwd2:sub(1,pwd2:find("[^/]*%.lua")-1)
  else
    local path1 = string.cut(pwd1:sub(4),"/")
    local path2 = string.cut(pwd2,"/")
    for i = 1,#path2-1 do
      if path2[i] == ".." then
        table.remove(path1)
      else
        table.insert(path1,path2[i])
      end
    end
    pwd = pwd1:sub(1,3)
    for i = 1,#path1 do
      pwd = pwd..path1[i].."/"
    end
  end
  return pwd
end

Note: if you want to use this function in another OS than Windows, you have to change the io.popen("echo %cd%") in the line 15 to whatever command gives you present working directory in your OS, e.g. io.popen("pwd") for Linux, and the pwd2:sub(2,3) == ":/" in the line 18 to whatever represents the root directory in your OS, e.g. pwd2:sub(1,1) == "/" for Linux.

Note2: if you don't provide the source variable to the function via debug.getinfo(1).source when calling it, then it will return the path to the directory of the file containing this function. Therefore, if you want to get the directory of a file which you called via dofile or loadfile, you will have to give it the source, like this: getScriptDir(debug.getinfo(1).source).