Java: A synchronized method in the superclass acquires the same lock as one in the subclass, right?

Question

class A {
    public synchronized void myOneMethod() {
        // ...
    }
}

class B extends A {
    public synchronized void myOtherMethod() {
        // ...
    }
}
         


        

Answer 1

Just a small addition for people who might be interested in the future..

Additionally remember that locks in Java are reentrant. If they were not this code of yours would result in a deadlock since as you've indicated both operations require the same lock.