Java: A synchronized method in the superclass acquires the same lock as one in the subclass, right?

Question

class A {
    public synchronized void myOneMethod() {
        // ...
    }
}

class B extends A {
    public synchronized void myOtherMethod() {
        // ...
    }
}
         


        

Answer 1

Yes, synchronized is equivalent to synchronized(this).

To be more precise:

For a class (static) method, the lock associated with the Class object for the method's class is used. For an instance method, the lock associated with this (the object for which the method was invoked) is used.