How to get task name inside task in gulp

Question

I\'m using gulp-plumber + gulp-notify and want to put task name in gulp-notify as a title. following is the code i wrote, thanks in advance.

gulp.task(\'SOMETASK         


        

Answer 1

If you want to monkey-patch Gulp, the following will work with Gulp version 3.9.0:

var _gulpStart = gulp.Gulp.prototype.start;

var _runTask = gulp.Gulp.prototype._runTask;

gulp.Gulp.prototype.start = function (taskName) {
    this.currentStartTaskName = taskName;

    _gulpStart.apply(this, arguments);
};

gulp.Gulp.prototype._runTask = function (task) {
    this.currentRunTaskName = task.name;

    _runTask.apply(this, arguments);
};

gulp.task('jscs', function () {
    console.log('this.currentStartTaskName: ' + this.currentStartTaskName);
    console.log('this.currentRunTaskName: ' + this.currentRunTaskName);
});

gulp.task('jshint', function () {
    console.log('this.currentStartTaskName: ' + this.currentStartTaskName);
    console.log('this.currentRunTaskName: ' + this.currentRunTaskName);
});

gulp.task('build', ['jshint', 'jscs']);

Running gulp build will yield the following console output:

c:\project>gulp build
[16:38:54] Using gulpfile c:\project\gulpfile.js
[16:38:54] Starting 'jshint'...
this.currentStartTaskName: build
this.currentRunTaskName: jshint
[16:38:54] Finished 'jshint' after 244 μs
[16:38:54] Starting 'jscs'...
this.currentStartTaskName: build
this.currentRunTaskName: jscs
[16:38:54] Finished 'jscs' after 152 μs
[16:38:54] Starting 'build'...
[16:38:54] Finished 'build' after 3.54 μs