Generic method where T is type1 or type2

Question

Is there a way to declare a generic function that the generic type is of type1 or type2?

example:

public void Foo(T number)
{
}         


        

Answer 1

Use overloaded methods instead:

public void Foo(int number)
{
} 

public void Foo(long number)
{
}

You cannot perform arithmetical operations on generic types anyway. Note that you can pass an int value to a long parameter. It will automatically be converted to long. Having just a single method with a long parameter could therefore be sufficient.

Older programming languages worked after the principle "There can be only one". C# allows you to have several methods with the same name in the same class, interface or struct. These methods must have a different signature. This means, that they must have a different number of parameters or parameters with different types (or both). This is called method overloading.