Are parenthesis needed to get the address of a struct member from a pointer to the struct as in “&(s->var)” vs “&s->var”?

Question

I have a struct str *s;

Let var be a variable in s. Is &s->var equal to &(s->var)?

Answer 1

Yes.

(-> is higher precedence than &. See http://cppreference.com/wiki/language/operator_precedence)