Code in constructor with “void” not execute [closed]

Answer 1

When you write:

public Test() 
    {
        System.out.println("constructor");
    }

This is definitely a constructor. And, as you create first object of Test class by writing:

    Test t1 = new Test();

This would call your constructor for the first time, and the code you have written in print statement, that is, constructor would be printed on console. Remember, constructors are automatically called when you create an object of the class.

Second time you create object by writing:

    Test t2 = new Test();

This would call the same constructor, and print the same "constructor" on screen, but it would be second time.

So you get the answer as- constructor constructor

In the second case, when you write:

public void test()
    {
        System.out.println("constructor");
    }

your compiler would treat it as a method rather than a constructor.

Even if void does not return anything, it is a "return-type" and constructors can never have a return type, never. This does not mean that they do not return you anything, but they just do not have a return type.

So, a method is not called automatically when the object of the class is created. So, you should not expect same result.

Now, you get an empty output because compiler provides a dummy/default constructor to every class, even if you do not define it. And, this default constructor would be called everytime you create a object of the class, no matter if you call it explicitly or not!

a default constructor can be thought of written somewhere as:

test() {   }

so now you can imagine what happens when you create two objects, program would compile and run correctly, returning empty output to you!

I hope that helped you.