Why does an overridden function in the derived class hide other overloads of the base class?

Question

Consider the code :

#include 

class Base {
public: 
    virtual void gogo(int a){
        printf(\" Base :: gogo (int) \\n\");
    };

    v         


        

Answer 1

Name hiding makes sense because it prevents ambiguities in name resolution.

Consider this code:

class Base
{
public:
    void func (float x) { ... }
}

class Derived: public Base
{
public:
    void func (double x) { ... }
}

Derived dobj;

If Base::func(float) was not hidden by Derived::func(double) in Derived, we would call the base class function when calling dobj.func(0.f), even though a float can be promoted to a double.

Reference: http://bastian.rieck.ru/blog/posts/2016/name_hiding_cxx/