SQL Query For Total Points Within Radius of a Location

Question

I have a database table of all zipcodes in the US that includes city,state,latitude & longitude for each zipcode. I also have a database table of points that each have a lat

Answer 1

MySQL Guru or not, the problem is that unless you find a way of filtering out various rows, the distance needs to be calculated between each point and each city...

There are two general approaches that may help the situation

• make the distance formula simpler
• filter out unlikely candidates to the 100k radius from a given city

Before going into these two avenue of improvement, you should decide on the level of precision desired with regard to this 100 miles distance, also you should indicate which geographic area is covered by the database (is this just continental USA etc.

The reason for this is that while more precise numerically, the Great Circle formula, is very computationally expensive. Another avenue of performance improvement would be to store "Grid coordinates" of sorts in addtion (or instead of) the Lat/Long coordinates.

Edit:
A few ideas about a simpler (but less precise) formula:
Since we're dealing with relatively small distances, (and I'm guessing between 30 and 48 deg Lat North), we can use the euclidean distance (or better yet the square of the euclidean distance) rather than the more complicated spherical trigonometry formulas.
depending on the level of precision expected, it may even be acceptable to have one single parameter for the linear distance for a full degree of longitude, taking something average over the area considered (say circa 46 statute miles). The formula would then become

  LatDegInMi = 69.0
  LongDegInMi = 46.0
  DistSquared = ((Lat1 - Lat2) * LatDegInMi) ^2 + ((Long1 - Long2) * LongDegInMi) ^2

On the idea of a columns with grid info to filter to limit the number of rows considered for distance calculation.
Each "point" in the system, be it a city, or another point (?delivery locations, store locations... whatever) is assigned two integer coordinate which define the square of say 25 miles * 25 miles where the point lies. The coordinates of any point within 100 miles from the reference point (a given city), will be at most +/- 4 in the x direction and +/- 4 in the y direction. We can then write a query similar to the following

SELECT city, state, latitude, longitude, COUNT(*)
FROM zipcodes Z
JOIN points P 
  ON P.GridX IN (
    SELECT GridX - 4, GridX - 3, GridX - 2, GridX - 1, GridX, GridX +1, GridX + 2 GridX + 3, GridX +4
   FROM zipcode ZX WHERE Z.id = ZX.id)
  AND
   P.GridY IN (
    SELECT GridY - 4, GridY - 3, GridY - 2, GridY - 1, GridY, GridY +1, GridY + 2 GridY + 3, GridY +4
   FROM zipcode ZY WHERE Z.id = ZY.id)
WHERE P.Status = A
   AND ((Z.latitude - P.latitude) * LatDegInMi) ^2 
      + ((Z.longitude - P.longitude) * LongDegInMi) ^2 < (100^2)
GROUP BY city,state,latitude,longitude;

Note that the LongDegInMi could either be hardcoded (same for all locations within continental USA), or come from corresponding record in the zipcodes table. Similarly, LatDegInMi could be hardcoded (little need to make it vary, as unlike the other it is relatively constant).

The reason why this is faster is that for most records in the cartesian product between the zipcodes table and the points table, we do not calculate the distance at all. We eliminate them on the basis of a index value (the GridX and GridY).

This brings us to the question of which SQL indexes to produce. For sure, we may want: - GridX + GridY + Status (on the points table) - GridY + GridX + status (possibly) - City + State + latitude + longitude + GridX + GridY on the zipcodes table

An alternative to the grids is to "bound" the limits of latitude and longitude which we'll consider, based on the the latitude and longitude of the a given city. i.e. the JOIN condition becomes a range rather than an IN :

JOIN points P 
  ON    P.latitude > (Z.Latitude - (100 / LatDegInMi)) 
    AND P.latitude < (Z.Latitude + (100 / LatDegInMi)) 
    AND P.longitude > (Z.longitude - (100 / LongDegInMi)) 
    AND P.longitude < (Z.longitude + (100 / LongDegInMi))