How does one go about sorting a vector containing custom (i.e. user defined) objects.
Probably, standard STL algorithm sort along with a predicate (a fu
A simple example using std::sort
struct MyStruct
{
int key;
std::string stringValue;
MyStruct(int k, const std::string& s) : key(k), stringValue(s) {}
};
struct less_than_key
{
inline bool operator() (const MyStruct& struct1, const MyStruct& struct2)
{
return (struct1.key < struct2.key);
}
};
std::vector < MyStruct > vec;
vec.push_back(MyStruct(4, "test"));
vec.push_back(MyStruct(3, "a"));
vec.push_back(MyStruct(2, "is"));
vec.push_back(MyStruct(1, "this"));
std::sort(vec.begin(), vec.end(), less_than_key());
Edit: As Kirill V. Lyadvinsky pointed out, instead of supplying a sort predicate, you can implement the operator<
for MyStruct
:
struct MyStruct
{
int key;
std::string stringValue;
MyStruct(int k, const std::string& s) : key(k), stringValue(s) {}
bool operator < (const MyStruct& str) const
{
return (key < str.key);
}
};
Using this method means you can simply sort the vector as follows:
std::sort(vec.begin(), vec.end());
Edit2: As Kappa suggests you can also sort the vector in the descending order by overloading a >
operator and changing call of sort a bit:
struct MyStruct
{
int key;
std::string stringValue;
MyStruct(int k, const std::string& s) : key(k), stringValue(s) {}
bool operator > (const MyStruct& str) const
{
return (key > str.key);
}
};
And you should call sort as:
std::sort(vec.begin(), vec.end(),greater());