Extract year from string and append to dataframe

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失恋的感觉
失恋的感觉 2021-02-11 02:07

I have a wine dataset with a column called \"title\" which contains the title of the wine including its vintage year. Refer sample:

  • Pull 2013 Chardonnay (Paso Robl
1条回答
  •  悲&欢浪女
    2021-02-11 02:32

    you can use sub() or regexec() from base by searching for numbers with have 4 digits:

    string <- c('R2 2013 Camp 4 Vineyard Grenache Blanc', 'Santa Ynez Valley 1999', 'dsdd 2015')
    sub("^.*([0-9]{4}).*", "\\1", string)
    unlist(regmatches(string, regexec("[0-9]{4}", string)))
    

    for your case:

    # create a helper function
    yearExtract <- function(string) {
      t <- regmatches(string, regexec("[0-9]{4}", string))
      sapply(t, function(x) {
        if(length(x) > 0){
          return(as.numeric(x))
        } else {
          return(NA)    
        }
      })
    }
    
    
    # create data.frame
    title <- c('R2 2013 Camp 4 Vineyard Grenache Blanc', 'Santa Ynez Valley 1999', 'dsdd 15')
    distributor <- c('a', 'b', 'd')
    wine_tidy2 <- data.frame(title, distributor)
    
    wine_tidy2$vintage_year <- yearExtract(as.character(wine_tidy2$title))
    

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