Transpose rows into column in unix

Question

I have input file which is given below

Input file

10,9:11/61432568509
118,1:/20130810014023
46,440:4/GTEL
10,9:11/61432568509
118,1:/20130810014023
46,44         


        

Answer 1

One way with awk:

$ awk -v RS= -F'\n' 'BEGIN{OFS=","}{for (i=1;i<=NF; i=i+3) {print $i,$(i+1),$(i+2)}}' file
10,9:11/61432568509,118,1:/20130810014023,46,440:4/GTEL
10,9:11/61432568509,118,1:/20130810014023,46,440:4/GTEL

It defines each field to be a line. Hence, it prints them on blocks of three.