Transpose rows into column in unix

Question

I have input file which is given below

Input file

10,9:11/61432568509
118,1:/20130810014023
46,440:4/GTEL
10,9:11/61432568509
118,1:/20130810014023
46,44         


        

Answer 1

if each of your "data block" has 3 lines, you could do:

sed -n 'N;N;s/\n/,/g;p' file

if you love awk:

awk 'NR%3{printf "%s,",$0;next}7' file