c++ difference between reinterpret cast and c style cast

后端 未结 4 1271
栀梦
栀梦 2021-02-10 17:38

Code:

char keyStr[50]={ 0x5F, 0x80 /* bla bla */ };
uint32_t* reCast  = reinterpret_cast< uint32_t* >( &keyStr[29] );
uint32_t* reCast2 = ( uint32_t* )         


        
4条回答
  •  情话喂你
    2021-02-10 18:04

    In what way do you mean "not dangerous"? reinterpret_cast is incredibly dangerous. It tells the compiler it is safe to ignore what it thinks it knows about the value.

    It's not as dangerous as a c-style cast which throws away the const/volatileness of the value in question as well as any information about what it is pointing to.

    Understanding these operations in assembly language is a bit pointless. They aren't assembly language constructs. They're C++ language constructs, that work something as follows:

    static_cast - Effectively this converts an object from one type to another. Note this can change the value (static_cast(1) doesn't have the same bit pattern as 1 for instance).

    dynamic_cast - if this object can be considered to be another type through inheritance, then treat it as such, otherwise render it as zero. This won't change the value of a pointer but it does safely change the compilers view of it.

    const_cast - throw away const (or volatile) qualifiers, which is not often a good idea as it allows you to destroy data the client thought was safe.

    reinterpret_cast - treat the bit pattern as meaning something different to what the compiler thought it did. Usually used for pointers and hopefully rarely. reinterpret_casting an int into a float is unlikely to be a good idea, but it will keep the same bit pattern.

    c-style-cast - Take the bit pattern, forget completely what you know about it, and treat it as something else. A dangerous and almost invisible combination of static_cast, reinterpret_cast and const_cast. It's not considered a good idea in C++ code because it's hard to spot in a review, and because it is not specific about what is happening.

提交回复
热议问题