Open a project file in phone7

Question

Howdy, I have a project in VisualStudio which contains a folder \'xmlfiles\' below the root node. This folder contains a file \'mensen.xml\' which I try to open ...

Howe

Answer 1

If you are just opening it to read it then you can do the following (Assuming you have set the Build Action of the file to Resource):

System.IO.Stream myFileStream = Application.GetResourceStream(new Uri(@"/YOURASSEMBLY;component/xmlfiles/mensen.xml",UriKind.Relative)).Stream;

If you are attempting to read/write this file then you will need to copy it to Isolated Storage. (Be sure to add using System.IO.IsolatedStorage)

You can use these methods to do so:

 private void CopyFromContentToStorage(String fileName)
 {
   IsolatedStorageFile store = IsolatedStorageFile.GetUserStoreForApplication();
   System.IO.Stream src = Application.GetResourceStream(new Uri(@"/YOURASSEMBLY;component/" + fileName,UriKind.Relative)).Stream;
   IsolatedStorageFileStream dest = new IsolatedStorageFileStream(fileName, System.IO.FileMode.OpenOrCreate, System.IO.FileAccess.Write, store);
   src.Position = 0;
   CopyStream(src, dest);
   dest.Flush();
   dest.Close();
   src.Close();
   dest.Dispose();
 }

 private static void CopyStream(System.IO.Stream input, IsolatedStorageFileStream output)
 {
   byte[] buffer = new byte[32768];
   long TempPos = input.Position;
   int readCount;
   do
   {
     readCount = input.Read(buffer, 0, buffer.Length);
     if (readCount > 0) { output.Write(buffer, 0, readCount); }
   } while (readCount > 0);
   input.Position = TempPos;
 }

In both cases, be sure the file is set to Resource and you replace the YOURASSEMBLY part with the name of your assembly.

Using the above methods, to access your file just do this:

IsolatedStorageFile store = IsolatedStorageFile.GetUserStoreForApplication();
if (!store.FileExists(fileName))
{
  CopyFromContentToStorage(fileName);
}
store.OpenFile(fileName, System.IO.FileMode.Append);