Linux: How to put a load on system memory?

Question

I\'m working on a small function, that gives my users a picture of how occupied the CPU is.

I\'m using cat /proc/loadavg, which returns the well known 3 num

Answer 1

I took this program and modify the line: mem = 1024*1024*512; //512 mb to say this: mem = 1*1024*1024*1024; //1 GB and compile it.

$ gcc iss_mem.c -o iss_mem

And write a bash wrapper around the compiled version of the C program above. It helps me generate a lot of memory load in my server.

#!/bin/bash
# Author: Mamadou Lamine Diatta
#         Senior Principal Consultant / Infrastructure Architect
# Email:  diatta at post dot harvard dot edu
# --------------------------------------------------------------------------------------
# *************************************************************************************

memsize_kb=`grep -i MemTotal /proc/meminfo | awk '{print $2}'`
MemTotal=$(($memsize_kb*1024))
for i in `seq 1 50`
do

        echo "`date +"%F:%H:%M:%S"` ----------------- Running [ $i ] iteration(s)"
        MemToAlloc=$((1*1024*1204*1204))
            # 1Gb of memory per iss_mem call
        TRESHOLD=$(($MemTotal/$MemToAlloc))
             # We are not supposed to make the system
             # run out of memory
        rand=1000
            # High enough to force a new one
        while (( $rand > $TRESHOLD ))
        do
                rand=$(($RANDOM/1000))
        done
        if [ $rand -eq 0 ]
        then
                rand=1
        fi

        echo `date +"%F:%H:%M:%S"` Running $rand iss_mem in parallel ...
        for j in `seq 1 $rand`
        do
             ${ISSHOME}/bin/iss_mem > /dev/null &
                # NOTE: gcc iss_mem.c -o iss_mem
        done

        sleep 180
        jobs -p
        kill `jobs -p`

        sleep 30


done
# -------------------------------------------------------------------------------------
# *************************************************************************************