Base Copy constructor not called

Question

class Base
{
      public:
      int i;

      Base()
      {
          cout<<\"Base Constructor\"<

        

Answer 1

Thank you very much. I got it. It means that the call to the base class copy constructor is automagivccally done in the derived's default copy constructor. Whereas in the second case since i am writing the derived's copy constructor i must make an explicit call to the base's copy constructor. Thanks again