How can I determine the angle a line found by HoughLines function using OpenCV?

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我在风中等你
我在风中等你 2021-02-10 05:48

Using the HoughLines function in OpenCV, is it possible to determine the angle of a resulting line relative to the base of the image?

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  •  清酒与你
    2021-02-10 06:25

    If you use HoughLines function, it will provide you lines already defined by two parameters: theta and rho, as

    vector lines;
    // detect lines
    HoughLines(image, lines, 1, CV_PI/180, 150, 0, 0 );
    
    // get lines
    for( size_t i = 0; i < lines.size(); i++ )
    {
        float rho = lines[i][0], theta = lines[i][1];
       ....
    }
    

    Or if you apply HoughLinesP function, you will get lines defined by two points, you just need to calculate the angle of line between two points with regard to the image, as:

    vector lines;
    // detect the lines
    HoughLinesP(image, lines, 1, CV_PI/180, 50, 50, 10 );
    for( size_t i = 0; i < lines.size(); i++ )
    {
        Vec4i l = lines[i];
        // draw the lines
    
        Point p1, p2;
        p1=Point(l[0], l[1]);
        p2=Point(l[2], l[3]);
        //calculate angle in radian,  if you need it in degrees just do angle * 180 / PI
        float angle = atan2(p1.y - p2.y, p1.x - p2.x);
      .......
    }
    

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