I am dynamically allocating a struct which has a different struct as a member:
struct a {
// other members
struct b;
}
struct b
First, let's get some real definitions in place to make this concrete.
struct b {
int x;
};
struct a_with_b {
struct b b;
}
struct a_with_b_ptr {
struct b *bp;
}
When you encapsulate a struct, you just need to allocate the outer struct (and since the inner struct is not a pointer, you use .
to reference members of the innert struct):
struct a_with_b *a1 = malloc(sizeof(struct a_with_b));
a1->b.x = 3;
But when you encapsulate a pointer, you have to allocate each independently and use ->
when referencing members of the inner struct:
struct a_with_b_ptr *a2 = malloc(sizeof(struct a_with_b_ptr));
a1->b = malloc(sizeof(struct b));
a1->b->x = 3;