SQL Query: Need order by count, most must be on top, the rest follows

Question

TABLEA

JobCode Job1 Job2 Job3 zip
------- ---- ---- ---- ----------
F       F    S    NULL 90030
F       F    S    NULL 90031
F       F    S    NULL 90031
F              


        

Answer 1

SQL Server 2008 using COUNT() OVER

select *, c = count(1) over (partition by zip)
from tbl
order by c desc;

If you don't need to see the additional column, then you can move the COUNT() OVER clause into the ORDER BY clause.

select JobCode, Job1, Job2, Job3, zip
from tbl
order by count(1) over (partition by zip) desc;