What is the Java equivalent to this preg_replace?

Question

wordword word\";
    $str = preg_replace(\"/word(?!([^<]+)?>)/i\",\"repl\",$str);
    echo $str;         


        

Answer 1

To translate that regex for use in Java, all you have to do is get rid of the / delimiters and change the trailing i to an inline modifier, (?i). But it's not a very good regex; I would use this instead:

(?i)word(?![^<>]++>)

According to RegexBuddy's Debug feature, when it tries to match the word in , the original regex requires 23 steps to reject it, while this one takes only seven steps. The actual Java code is

str = str.replaceAll("(?i)word(?![^<>]++>)", "repl");