I want to write a R-squared term for my legend but I do not know how. Could someone help me please? My legend syntax is:
legend(2,10, c(\"BW (MPE=3%, R-squared=0
This is less complex than using c( as.expression ( bquote...
multiple times:
plot(1:10)
legend(2, 10, expression("BW (MPE = 3%," ~ R^2 ~ "= 0.77)",
"MY (MPE = 5%," ~ R^2 ~ "= 0.80)"),
pch=c(2,3))
It is useful to understand that the expression
function is really a way to make lists of expressions and that commas are then reserved as separators for that process. This means you cannot have a "naked" comma in something you want to be inside one of the distinct elements. The commas immediately after the %
-signs are protected from parsing by the quotes. This could fully plotmath()-ified with:
plot(1:10)
legend(2, 10, expression(BW * list(MPE == 3*'%',
R^2 == 0.77),
MY * list( MPE == 5*'%',
R^2 == 0.80)
),
pch=c(2,3))
That way the only character needing special attention is the '%'-sign which plotmath() uses to delimit its specials.