Slug Url Regex in Django

Question

After reading a lot about proper use of a slug to create a detail view from a list of objects. However, I am still having problems getting it to work for me. I am displaying a l

Answer 1

You're not passing any arguments to build the detail URL. You probably want to do this:

{% url "detail" thing.slug %}

Which will create a detail URL with the given slug filled in.