' << ' operator in verilog

Question

i have a verilog code in which there is a line as follows:

parameter ADDR_WIDTH = 8 ;
parameter RAM_DEPTH = 1 << ADDR_WIDTH;

here what wi

Answer 1

<< is the left-shift operator, as it is in many other languages.

Here RAM_DEPTH will be 1 left-shifted by 8 bits, which is equivalent to 2^8, or 256.