Operator precedence and evaluation order

Question

I can\'t understand output of this program:

#include
using namespace std;
int main()
{
    int x = 1 , y = 1, z = 1;
    cout << ( ++x || +         


        

Answer 1

This expression

 ++x || ++y && ++z

is equivalent to expression

++x || ( ++y && ++z )

and not like this

 ( ++x || ++y ) && ++z

If the first operand of the logical OR expression is evaluated to true (as in your example) then the second operand that is ( ++y && ++z ) is not evaluated.