Wait until all promises complete even if some rejected

Question

Let\'s say I have a set of Promises that are making network requests, of which one will fail:

// http://does-not-exist will throw a TypeError
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Answer 1

I've been using following codes since ES5.

Promise.wait = function(promiseQueue){
    if( !Array.isArray(promiseQueue) ){
        return Promise.reject('Given parameter is not an array!');
    }

    if( promiseQueue.length === 0 ){
        return Promise.resolve([]);
    }

    return new Promise((resolve, reject) =>{
        let _pQueue=[], _rQueue=[], _readyCount=false;
        promiseQueue.forEach((_promise, idx) =>{
            // Create a status info object
            _rQueue.push({rejected:false, seq:idx, result:null});
            _pQueue.push(Promise.resolve(_promise));
        });

        _pQueue.forEach((_promise, idx)=>{
            let item = _rQueue[idx];
            _promise.then(
                (result)=>{
                    item.resolved = true;
                    item.result = result;
                },
                (error)=>{
                    item.resolved = false;
                    item.result = error;
                }
            ).then(()=>{
                _readyCount++;

                if ( _rQueue.length === _readyCount ) {
                    let result = true;
                    _rQueue.forEach((item)=>{result=result&&item.resolved;});
                    (result?resolve:reject)(_rQueue);
                }
            });
        });
    });
};

The usage signature is just like Promise.all. The major difference is that Promise.wait will wait for all the promises to finish their jobs.