Wait until all promises complete even if some rejected

Question

Let\'s say I have a set of Promises that are making network requests, of which one will fail:

// http://does-not-exist will throw a TypeError
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Answer 1

I think the following offers a slightly different approach... compare fn_fast_fail() with fn_slow_fail()... though the latter doesn't fail as such... you can check if one or both of a and b is an instance of Error and throw that Error if you want it to reach the catch block (e.g. if (b instanceof Error) { throw b; }) . See the jsfiddle.

var p1 = new Promise((resolve, reject) => { 
    setTimeout(() => resolve('p1_delayed_resolvement'), 2000); 
}); 

var p2 = new Promise((resolve, reject) => {
    reject(new Error('p2_immediate_rejection'));
});

var fn_fast_fail = async function () {
    try {
        var [a, b] = await Promise.all([p1, p2]);
        console.log(a); // "p1_delayed_resolvement"
        console.log(b); // "Error: p2_immediate_rejection"
    } catch (err) {
        console.log('ERROR:', err);
    }
}

var fn_slow_fail = async function () {
    try {
        var [a, b] = await Promise.all([
            p1.catch(error => { return error }),
            p2.catch(error => { return error })
        ]);
        console.log(a); // "p1_delayed_resolvement"
        console.log(b); // "Error: p2_immediate_rejection"
    } catch (err) {
        // we don't reach here unless you throw the error from the `try` block
        console.log('ERROR:', err);
    }
}

fn_fast_fail(); // fails immediately
fn_slow_fail(); // waits for delayed promise to resolve