Rule for lambda capture variable

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忘了有多久
忘了有多久 2021-02-09 01:53

For example:

class Example
{
public:
    explicit Example(int n) : num(n) {}
    void addAndPrint(vector& v) const
    {
        for_each(v.begin(         


        
2条回答
  •  粉色の甜心
    2021-02-09 02:42

    Standard says the following (5.1.2):

    The identifiers in a capture-list are looked up using the usual rules for unqualified name lookup (3.4.1); each such lookup shall find a variable with automatic storage duration declared in the reaching scope of the local lambda expression.

    To my understanding GCC compiler is right because 'num' is in the reaching scope at the point of lambda declaration.

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