In copy-initialization, is the call to the copy constructor explicit or implicit?

Question

class AAA {
public:
    explicit AAA(const AAA&) {}
    AAA(int) {}
};


int main() {
    AAA a = 1;
    return 0;
}

In the above code, as I unders

Answer 1

Looks like copy constructor is never called . Only constructor is called . The following code may call copy constructor

AAA a = 1;
AAA ab = a;

Not sure why G++ is compiling it .