How to ensure that we read all lines from boost::child process

Question

I saw the following code on boost::child documentation page where they explain how to read the output of a child process. http://www.boost.org/doc/libs/1_64_0/doc/h

Answer 1

I think there's no proper way unless you use asynchronous methods.

Perhaps you can simple get a future to a vector and use string_views into that if you somehow really need it line-by-line.

std::future > output, error;

boost::asio::io_service svc;
bp::child c(bp::search_path("nm"), file, bp::std_out > output, bp::std_err > error, svc);
svc.run();

To read exactly like you did before you can use an istream on top of the vector:

#include 
#include 
#include 
#include 

namespace bp = boost::process;
namespace bio = boost::iostreams;
std::string const file = "./a.out";

int main() {
    std::future > output, error;

    boost::asio::io_service svc;
    bp::child c(bp::search_path("nm"), file, bp::std_out > output, bp::std_err > error, svc);
    svc.run();

    //then later
    {
        auto raw = output.get();
        std::vector data;
        std::string line;
        bio::stream_buffer sb(raw.data(), raw.size());
        std::istream is(&sb);

        while (std::getline(is, line) && !line.empty())
            data.push_back(line);

        std::cout << data.at(rand()%data.size()) << "\n";
    }

}