iPhoneX and Notch detection

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迷失自我
迷失自我 2021-02-08 21:14

Using Javascript; how can I check if the users device is an iPhoneX?

Also, how can I determine what side the iPhones\' \'notch\' is positioned when in the landscape ori

2条回答
  •  清酒与你
    2021-02-08 21:46

    So I've come up with a method of detecting the iPhoneX with Javascript. My process also checks for the position of the Notch depending on the users device orientation:

    https://codepen.io/marknotton/pen/NwpgBK

    (function(window){
    
      // Really basic check for the ios platform
      // https://stackoverflow.com/questions/9038625/detect-if-device-is-ios
      var iOS = /iPad|iPhone|iPod/.test(navigator.userAgent) && !window.MSStream;
    
      // Get the device pixel ratio
      var ratio = window.devicePixelRatio || 1;
    
      // Define the users device screen dimensions
      var screen = {
        width : window.screen.width * ratio,
        height : window.screen.height * ratio
      };
    
      // iPhone X Detection
      if (iOS && screen.width == 1125 && screen.height === 2436) {
    
        // Set a global variable now we've determined the iPhoneX is true
        window.iphoneX = true;
    
        // Adds a listener for ios devices that checks for orientation changes.
        window.addEventListener('orientationchange', update);
        update();
      }
    
      // Each time the device orientation changes, run this update function
      function update() {
        notch();
        iphoneXChecker();
      }
    
      // Notch position checker
      function notch() {
    
        var _notch = '';
    
        if( 'orientation' in window ) {
          // Mobile
          if (window.orientation == 90) {
            _notch = 'left';
          } else if (window.orientation == -90) {
            _notch = 'right';
          }
        } else if ( 'orientation' in window.screen ) {
          // Webkit
          if( screen.orientation.type === 'landscape-primary') {
            _notch = 'left';
          } else if( screen.orientation.type === 'landscape-secondary') {
            _notch = 'right';
          }
        } else if( 'mozOrientation' in window.screen ) {
          // Firefox
          if( screen.mozOrientation === 'landscape-primary') {
            _notch = 'left';
          } else if( screen.mozOrientation === 'landscape-secondary') {
            _notch = 'right';
          }
        }
    
        window.notch = _notch;
      }
    
    })(window);
    
    // Bespoke functions:
    // The above functions have no jQuery Dependencies.
    // The below code uses jQuery solely for this quick demo.
    if ( window.iphoneX === true ) {
      $('body').addClass('iphoneX');
    }
    function iphoneXChecker() {
      if (window.notch == 'left') {
        $('body').removeClass('notch-right').addClass('notch-left');
      } else if (window.notch == 'right') {
        $('body').removeClass('notch-left').addClass('notch-right');
      } else {
        $('body').removeClass('notch-right notch-left');
      }
    }
    

    I can't help but feel like this is just a combination of little hacks. As you'll probably notice; my Javascript isn't exactly to a high standard and I'm sure there are better/cleaner ways to do this.

    I'd be very happy to receive feedback and solutions to issues I've not considered.


    If you just want to check for the iPhoneX (ignoring the Notch), this should do the job:

    https://codepen.io/marknotton/pen/MOpodJ

    (function(){
    
      // Really basic check for the ios platform
      // https://stackoverflow.com/questions/9038625/detect-if-device-is-ios
      var iOS = /iPad|iPhone|iPod/.test(navigator.userAgent) && !window.MSStream;
    
      // Get the device pixel ratio
      var ratio = window.devicePixelRatio || 1;
    
      // Define the users device screen dimensions
      var screen = {
        width : window.screen.width * ratio,
        height : window.screen.height * ratio
      };
    
      // iPhone X Detection
      if (iOS && screen.width == 1125 && screen.height === 2436) {
        alert('iPhoneX Detected!');
      }
    })();
    

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