Get position of an item within a ListView?

Question

How would one find the position of a specific item within a ListView? (Populated by SimpleCursorAdapter).

The reason I ask: The listview is set to singleChoice mode. Whe

Answer 1

You should try

//SimpleCursorAdapter adapter;
final int position = adapter.getCursor().getPosition();

API Docs:

public abstract int getPosition () 

Since: API Level 1

Returns the current position of the cursor in the row set. The value is zero-based. When the row set is first returned the cursor will be at positon -1, which is before the first row. After the last row is returned another call to next() will leave the cursor past the last entry, at a position of count().

Returns the current cursor position.

Update

To get an item's position based on the id used by the adapter:

private int getItemPositionByAdapterId(final long id)
{
    for (int i = 0; i < adapter.getCount(); i++)
    {
        if (adapter.getItemId(i) == id)
            return i;
    }
    return -1;
}

To get an item's position based on the underlying object's properties (member values)

//here i use `id`, which i assume is a member of a `MyObject` class, 
//and this class is used to represent the data of the items inside your list:
private int getItemPositionByObjectId(final long id)
{
    for (int i = 0; i < adapter.getCount(); i++)
    {
        if (((MyObject)adapter.getItem(i)).getId() == id)
            return i;
    }
    return -1;
}