I recently tried implementing the SimpleHTTPRequestHandler to accept AJAX requests according to this.
Although everything seems to work as far as receiving the request f
Make sure your response has a send_header() with a content type. I have seen AJAX requests get confused without this. You can also try switching your POST to a GET for debugging and make sure the browser can see the content.
Here is a simple HTTP example for returning XML if you point your query or browser to 127.0.0.1/test:
import SimpleHTTPServer, SocketServer
import urlparse
PORT = 80
class MyHandler(SimpleHTTPServer.SimpleHTTPRequestHandler):
def do_GET(self):
# Parse query data & params to find out what was passed
parsedParams = urlparse.urlparse(self.path)
queryParsed = urlparse.parse_qs(parsedParams.query)
# request is either for a file to be served up or our test
if parsedParams.path == "/test":
self.processMyRequest(queryParsed)
else:
# Default to serve up a local file
SimpleHTTPServer.SimpleHTTPRequestHandler.do_GET(self);
def processMyRequest(self, query):
self.send_response(200)
self.send_header('Content-Type', 'application/xml')
self.end_headers()
self.wfile.write("");
self.wfile.write("Some XML ");
self.wfile.close();
Handler = MyHandler
httpd = SocketServer.TCPServer(("", PORT), Handler)
print "serving at port", PORT
httpd.serve_forever()