get absolute path to apache webcontents folder from a java class file [duplicate]

Answer 1

Method -1 :

//step1 : import java.net.InetAddress;

InetAddress ip = InetAddress.getLocalHost();

//step2 : provide your file path

String filepath="GIVE YOUR FILE PATH AFTER WEB FOLDER something like /images/grid.png"

//step3 : grab all peices together

String a ="http://"+ip.getHostAddress()+":"+request.getLocalPort()+""+request.getServletContext().getContextPath()+filepath;

Method - 2 :

//Step : 1-get the absolute url

String path = request.getRequestURL().toString();

//Step : 2-then sub string it with the context path

path = path.substring(0, path.indexOf(request.getContextPath()));

//step : 3-provide your file path after web folder

String finalPath = "GIVE YOUR FILE PATH AFTER WEB FOLDER something like /images/grid.png"
path +=finalPath;

MY SUGGESTION

1. keep the file which you want to open in the default package of your source folder and open the file directly to make things simple and clear.
   NOTE : this happens because it is present in the class path of your IDE if you are coding without IDE then keep it in the place of your java compiled class file or in a common folder which you can access.

HAVE FUN