Explanation of the safe average of two numbers

Question

Whenever I need to average two numbers for an algorithm like binary search, I always do something like this:

int mid = low + ((high - low) / 2);

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Answer 1

You cannot use an unsigned int in Java. In case of overflow, the low 32 bits are considered, and the high order bits are discarded. The unsigned right shift will help u treat the int as unsigned int. However, in C++ you won't have the overflow.