What's the most efficient way to make bitwise operations in a C array

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死守一世寂寞
死守一世寂寞 2021-02-08 13:24

I have a C array like:

char byte_array[10];

And another one that acts as a mask:

char byte_mask[10];

I would

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  •  逝去的感伤
    2021-02-08 14:08

    for ( i = 10 ; i-- > 0 ; )
        result_array[i] = byte_array[i] & byte_mask[i];
    
    • Going backwards pre-loads processor cache-lines.
    • Including the decrement in the compare can save some instructions.

    This will work for all arrays and processors. However, if you know your arrays are word-aligned, a faster method is to cast to a larger type and do the same calculation.

    For example, let's say n=16 instead of n=10. Then this would be much faster:

    uint32_t* input32 = (uint32_t*)byte_array;
    uint32_t* mask32 = (uint32_t*)byte_mask;
    uint32_t* result32 = (uint32_t*)result_array;
    for ( i = 4 ; i-- > 0 ; )
        result32[i] = input32[i] & mask32[i];
    

    (Of course you need a proper type for uint32_t, and if n is not a power of 2 you need to clean up the beginning and/or ending so that the 32-bit stuff is aligned.)

    Variation: The question specifically calls for the results to be placed in a separate array, however it would almost certainly be faster to modify the input array in-place.

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