Create a random order of (x, y) pairs, without repeating/subsequent x's

Question

Say I have a list of valid X = [1, 2, 3, 4, 5] and a list of valid Y = [1, 2, 3, 4, 5].

I need to generate all combinations of every element in

Answer 1

A simple solution to ensure an average O(N*M) complexity:

def pseudorandom(M,N):
    l=[(x+1,y+1) for x in range(N) for y in range(M)]
    random.shuffle(l)
    for i in range(M*N-1):
            for j in range (i+1,M*N): # find a compatible ...
                if l[i][0] != l[j][0]:
                    l[i+1],l[j] = l[j],l[i+1]
                    break  
            else:   # or insert otherwise.
                while True:
                    l[i],l[i-1] = l[i-1],l[i]
                    i-=1
                    if l[i][0] != l[i-1][0]: break  
    return l

Some tests:

In [354]: print(pseudorandom(5,5))
[(2, 2), (3, 1), (5, 1), (1, 1), (3, 2), (1, 2), (3, 5), (1, 5), (5, 4),\
(1, 3), (5, 2), (3, 4), (5, 3), (4, 5), (5, 5), (1, 4), (2, 5), (4, 4), (2, 4),\ 
(4, 2), (2, 1), (4, 3), (2, 3), (4, 1), (3, 3)]

In [355]: %timeit pseudorandom(100,100)
10 loops, best of 3: 41.3 ms per loop