How do I check whether a file exists without exceptions?

Question

How do I check if a file exists or not, without using the try statement?

Answer 1

If the file is for opening you could use one of the following techniques:

with open('somefile', 'xt') as f: #Using the x-flag, Python3.3 and above
    f.write('Hello\n')

if not os.path.exists('somefile'): 
    with open('somefile', 'wt') as f:
        f.write("Hello\n")
else:
    print('File already exists!')

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UPDATE

Just to avoid confusion and based on the answers I got, current answer finds either a file or a directory with the given name.