Initialization makes pointer from integer without a cast - C

Question

Sorry if this post comes off as ignorant, but I\'m still very new to C, so I don\'t have a great understanding of it. Right now I\'m trying to figure out pointers.

I mad

Answer 1

Maybe you wanted to do this:

#include 

int change( int *b )
{
  *b = 4;
  return 0;
}

int main( void )
{
  int *b;
  int myint = 6;

  b = &myint;
  change( &b );
  printf( "%d", b );
  return 0;
}