Debugging Jquery ajax function

后端 未结 3 782
鱼传尺愫
鱼传尺愫 2021-02-08 08:59

JS code:

$.ajax({


        type: \'POST\',
         url: \'http://localhost/MyServiceDir/Service.asmx/Foo\',
         contentType: \'application/json; charset=u         


        
3条回答
提交回复
热议问题