create JSON string from SqlDataReader

Question

UPDATE

I figured it out. Check out my answer below.

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I\'m trying to create a JSON string representing a row from a database table to return in an HTTP res

Answer 1

Got it! Here's the C#...

// ... SQL connection and command set up, only querying 1 row from the table
StringBuilder sb = new StringBuilder();
StringWriter sw = new StringWriter(sb);
JsonWriter jsonWriter = new JsonTextWriter(sw);

try {

    theSqlConnection.Open(); // open the connection

    // read the row from the table
    SqlDataReader reader = sqlCommand.ExecuteReader();
    reader.Read();

    int fieldcount = reader.FieldCount; // count how many columns are in the row
    object[] values = new object[fieldcount]; // storage for column values
    reader.GetValues(values); // extract the values in each column

    jsonWriter.WriteStartObject();
    for (int index = 0; index < fieldcount; index++) { // iterate through all columns

        jsonWriter.WritePropertyName(reader.GetName(index)); // column name
        jsonWriter.WriteValue(values[index]); // value in column

    }
    jsonWriter.WriteEndObject();

    reader.Close();

} catch (SqlException sqlException) { // exception
    context.Response.ContentType = "text/plain";
    context.Response.Write("Connection Exception: ");
    context.Response.Write(sqlException.ToString() + "\n");
} finally {
    theSqlConnection.Close(); // close the connection
}
// END of method
// the above method returns sb and another uses it to return as HTTP Response...
StringBuilder theTicket = getInfo(context, ticketID);
context.Response.ContentType = "application/json";
context.Response.Write(theTicket);

... so the StringBuilder sb variable is the JSON object that represents the row I wanted to query. Here is the JavaScript...

$.ajax({
    type: 'GET',
    url: 'Preview.ashx',
    data: 'ticketID=' + ticketID,
    dataType: "json",
    success: function (data) {

        // data is the JSON object the server spits out
        // do stuff with the data
    }
});

Thanks to Scott for his answer which inspired me to come to my solution.

Hristo