malloc in an embedded system without an operating system

Question

This query is regarding allocation of memory using malloc.

Generally what we say is malloc allocates memory from heap.

Now say I have a

Answer 1

malloc() is a function that is usually implemented by the runtime-library. You are right, if you are running on top of an operating system, then malloc will sometimes (but not every time) trigger a system-call that makes the OS map some memory into your program's address space.

If your program runs without an operating system, then you can think of your program as being the operating system. You have access to all addresses, meaning you can just assign an address to a pointer, then de-reference that pointer to read/write.

Of course you have to make sure that not other parts of your program just use the same memory, so you write your own memory-manager:

To put it simply you can set-aside a range of addresses which your "memory-manager" uses to store which address-ranges are already in use (the datastructures stored in there can be as easy as a linked list or much much more complex). Then you will write a function and call it e.g. malloc() which forms the functional part of your memory-manager. It looks into the mentioned datastructure to find an address of ranges that is as long as the argument specifies and return a pointer to it.

Now, if every function in your program calls your malloc() instead of randomly writing into custom addresses you've done the first step. You can write a free()-function which will look for the pointer it is given in the mentioned datastructure, and adapts the datastructure (in the naive linked-list it would merge two links).