Add (collect) exit codes in bash

Question

I need to depend on few separate executions in a script and don\'t want to bundle them all in an ugly \'if\' statement. I would like to take the exit code \'$?\' of each executi

Answer 1

A quick experiment and dip into bash info says:

declare -i RESULT=$RESULT + $?

since you are adding to the result several times, you can use declare at the start, like this:

declare -i RESULT=0

true
RESULT+=$?
false
RESULT+=$?
false
RESULT+=$?

echo $RESULT
2

which looks much cleaner.

declare -i says that the variable is integer.

Alternatively you can avoid declare and use arithmetic expression brackets:

RESULT=$(($RESULT+$?))