How to get the “next” item in an OrderedDict?

Question

I\'m using an OrderedDict to random access a list, but now want the next item in the list from the one that I have:

foo = OrderedDict([(\'apple\', 4         


        

Answer 1

Reworked from your code, this way I guess would be a little better:

import collections as co
import datetime as dt
import itertools as it

foo = co.OrderedDict([
    (dt.date(2000,1,1), 4),
    (dt.date(2000,5,23), 3),
    (dt.date(2000,10,1), 2),
    (dt.date(2000,12,31), 1)
])
today = dt.date(2000,1,30)

fooiter = it.dropwhile(lambda d: d <= today, foo)
print next(fooiter)
print list(fooiter)

Basically having iterator at the right place is already enough.

Would be cool to start iteration from any position, but not sure if-how possible. Needs some thought.